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White raven [17]
3 years ago
5

In the given right angled triangle ABC, right

Mathematics
1 answer:
Vikki [24]3 years ago
6 0

The right angled triangle is missing, so i have attached it.

Answer:

Proved below

Step-by-step explanation:

From the attached image, we can see that QP is parallel to BC.

Now, looking at triangles AQP and ABC, we can see that;

∠ AQP = ∠ ABC

Also;

∠ APQ = ∠ ACB

This means that triangles ABC and AQP are similar.

We are told that P is the mid-point of AC.

Thus; AP = PC

We can now say that;

AP:AC = 1:2 and AQ:AB = 1:2

Since AQ:AB = 1:2, it means Q is the midpoint of AB.

Now, ∠ AQP = ∠ BQP

However, according to SAS congruence test, AQP is congruent to BQP.

Thus; AP = BP = CP

Since AP:AC = 1:2 as we saw earlier, then;

BP:AC = 1:2

Thus:

BP/AC = ½

BP = ½AC

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