Answer:
6*(61^2) and 61^3
Step-by-step explanation:
If the squares have a side length of 61 (assuming this is a cube) our surface area is 6*(61^2) because each side is a square and there are six sides.
As for the volume, we have 61^3.
Hope this was helpful.
~cloud
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Answer:the answer is 9,6
Step-by-step explanation:
I JUST TOOK THE QUIZ
30, you could just multiply both numbers, but it's also better to list out the factor until both match
Answer:
<em>H</em>₀: <em>μ₁ = μ₂= μ₃</em>
<em>Hₐ: </em>At least one of the means is different.
Step-by-step explanation:
Analysis of variance or ANOVA test is used to determine whether the means of different groups are similar or not.
The hypothesis of an ANOVA test for <em>n</em> homogeneous groups is:
In this case the researcher is testing whether the mean bone mineral density is different for the three different groups.
The hypothesis for this test can be defined as follows:
<em>H</em>₀: The mean bone mineral density is not different for the three different groups, i.e. <em>μ₁ = μ₂= μ₃</em>
<em>Hₐ: </em>The mean bone mineral density is different for the three different groups, i.e. at least one of the means is different.
