
is continuous over its domain, all real

.
Meanwhile,

is defined for real

.
If

, then we have

as the domain of

.
We know that if

and

are continuous functions, then so is the composite function

.
Both

and

are continuous on their domains (excluding the endpoints in the case of

), which means

is continuous over

.
Answer:
The answer to part B is B.
Step-by-step explanation:
Could you take another photo so I can see the bottom of the page?
Line CB touches circle A only at one point (point B), hence CB is a tangent.
<h3>What is a
circle?</h3>
A circle is the locus of a point such that its distance from a fixed point (center) is always constant.
When a line intersects a circle in exactly one point the line is said to be tangent to the circle
Hence since Line CB touches circle A only at one point (point B), hence CB is a tangent.
Find out more on circle at: brainly.com/question/24375372
Given the triangle
PQR
with points
P(8,0)
Q(6,2)
R(-2,-4)
And the triangle
P'Q'R'
with points
P'(4,0)
Q'(3,1)
R'(-1,-2)
Part A. Scale factor
Using the vertex
P( 8, 0)
P'(4,0)
the dilatation factor is given by

The triangle has a dilatation factor of 1/2
Part B:
P''Q''R'' after using P'Q'R' reflected about the y axis
to make a reflection over the y axis
coordinates (x,y) turn into coordinates (-x,y)
as follows



Then triangle P''Q''R'' has coordinates
P''(-4,0)
Q''(-3,1)
R''(1,-2)
Part C:
PQR is congruent to P''Q''R''?
Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.
Then the triangles are not congruent
I believe the answer either 4 or 6
Im not sure so if its wrong, sorry