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1 year ago

Can someone help me with this?

Mathematics

1 answer:

jekas [21]1 year ago

6 0

Answer:

$\huge\purple{ x^2 +(y+2)^2 = 4}$

Step-by-step explanation:

Circle is centred at (0, -2)

-> h = 0 & k = - 2

radius of the circle (r) = y-coordinate of the center = - 2

Equation of circle in standard form is given as:

$(x-h)^2 +(y-k)^2 = r^2$

Plugging the values of h, k and r in the above equation, we find:

$(x-0)^2 +[y-(-2)]^2 = (-2)^2$

$\implies\huge\orange{ x^2 +(y+2)^2 = 4}$

This is the required equation of circle.

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PLEASE HELP!

butalik [34]

We know for the problem that the performer earned $120 at a performance where 8 people attend. We also know that he uses 43% of the money earned to pay the costs involved in putting on each performance, so we need to find the 43% of $120. To do that, we are going to divide 43% by 100%, and then multiply it by $120:
 $\frac{43}{100}*120=51.6$
Now we know that the performer uses $51.6 of $120 to pay the costs involved in putting on each performance. The only thing left to find his profits is subtract $51.6 from $120:
$120-51.6=68.4$

We can conclude that the performer makes a profit of $68.4 when 8 people attend his performance.

3 0

3 years ago

How many windows would Carpenter A install in 10 hours?

DerKrebs [107]

Answer:

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Step-by-step explanation:

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2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

1 year ago

Which fraction has a repeating decimal as its decimal expansion? w w w cow

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

idk whats cow but w over co

8 0

2 years ago

Laura has a rectangular piece of wood that is 7in by 4in she wants to cover it with strips of ribbon that are 1/4 inch wide what

inn [45]

Answer: 112 inches.

Step-by-step explanation:

You know that the width of the rectangular piece of wood is 4 inches and the width of the strip ribbon is 1/4 inches.

Then, let be "n" the number of strips ribbon that Laura needs to cover the width of the rectangular piece of wood (Assuming that she will cover the wood in the form shown in the figure attached). This is:

$n=\frac{4in}{\frac{1}{4}in}\\\\n=16$

To find the lenght of ribbon that Laura needs to conver the wood, you must multiply the number of strips ribbon "n" by the lenght of the rectangular piece of wood, then you get:

$lenght=(16)(7in)\\lenght=112in$

8 0

3 years ago