Step-by-step explanation:
we know that=
other number=LCM×HCF\One number
=6×360 upon 24
=90
The answer is rarefraction
Explanation
I got it right for my test in class
Answer: the company should invest $12191 each week
Step-by-step explanation:
The amount that the company needs is $5,400,000
We would apply the periodic interest rate formula which is expressed as
P = a/[{(1+r)^n]-1}/{r(1+r)^n}]
Where
P represents the weekly payments.
a represents the amount that the company needs
r represents the rate.
n represents number of weekly payments. Therefore
a = 5,400000
There are 52 weeks in a year
r = 0.079/52 = 0.0015
n = 52 × 14 = 728
Therefore,
P = 5400000/[{(1+0.0015)^728]-1}/{0.0015(1+0.0015)^728}]
5400000/[{(1.0015)^728]-1}/{0.0015(1.0015)^728}]
P = 5400000/{2.98 -1}/[0.0015(2.98)]
P = 5400000/(1.98/0.00447)
P = 5400000/442.95
P = $12191
16.445 I have no expectation sorry.
Answer:
![f(x)=4\sqrt[3]{16}^{2x}](https://tex.z-dn.net/?f=f%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D)
Step-by-step explanation:
We believe you're wanting to find a function with an equivalent base of ...
![4\sqrt[3]{4}\approx 6.3496](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B4%7D%5Capprox%206.3496)
The functions you're looking at seem to be ...
![f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x](https://tex.z-dn.net/?f=f%28x%29%3D2%5Csqrt%5B3%5D%7B16%7D%5Ex%5Capprox%202%5Ccdot2.5198%5Ex%5C%5C%5C%5Cf%28x%29%3D2%5Csqrt%5B3%5D%7B64%7D%5Ex%3D2%5Ccdot%204%5Ex%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D%5Capprox%204%5Ccdot%206.3496%5Ex%5C%20%5Cleftarrow%5Ctext%7B%20this%20one%7D%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B64%7D%5E%7B2x%7D%3D4%5Ccdot%2016%5Ex)
The third choice seems to be the one you're looking for.
