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olasank [31]
3 years ago
15

Write an expression for the sequence of operations described below.

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0
(s÷t) - r is the correct expression.
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A factory whistle blows every 30 minutes. The clock tower chimes every 15 minutes. If they both sounded at 1:00 p.M.,at what tim
madam [21]

Answer:

1.30 p.M.

Step-by-step explanation:

The factory whistle blowed at 1:00 p.M, and it blows every 30 minutes, so it will blow again at 1:30 p.M.

The clock tower chimed at 1.00 p.M., and it chimes every 15 minutes, so it will chime again at 1:15 p.M, and after that, it will chime again at 1:30 p.M.

So, you will hear them both at the same time at 1:30 p.M.

We can also solve this problem using LCM:

the least commom multiple between 15 and 30 is 30, so we just need to sum 30 to the inicial time (1:00 p.M.), so the time they will "find each other" again is 1.30 p.M.

7 0
3 years ago
Please help and show work<br>​
Sunny_sXe [5.5K]

Answer:

Just do scan and solve by brainly really helpful ngl

Step-by-step explanation:

5 0
2 years ago
Which ordered pairs lie on the graph of the exponential function f(x) = 3 (1/4)x
sineoko [7]
The first two pairs.. just substitute the x-coordinate and find y
8 0
3 years ago
which of the following terms best describes the graph of the exponential function given below f(x)=4*5^x
N76 [4]
If i did it right the anwser is 20
4 0
3 years ago
Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se
Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}

\frac{1}{60} (1+6+2) = 0.15

b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}

= \frac{1}{3} 1.106 = 0.368

7 0
3 years ago
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