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2 years ago

10. In right triangle FGH shown below,

Mathematics

1 answer:

Vikki [24]2 years ago

5 0

Applying the leg rule, and solving algebraically, the lengths are determined as:

JG = 9

HJ = 12

The Leg rule states that when an altitude bisects the right angle of a right triangle and intersects the hypotenuse, then, hypotenuse/leg = leg/part.

Find length of JG using algebraic solutions and the leg rule:

Let JG = x

Hypotenuse = x + 16

Leg = 15

Part = x

Therefore:

(x + 16)/15 = 15/x (leg rule)

Cross multiply

x(x + 16) = (15)(15)

x² + 16x = 225

x² + 16x - 225 = 0

Factorize

(x + 25)(x − 9) = 0

x = -25 or x = 9

The length of JG (x) cannot be negative, therefore, the length of JG = 9.

Find length of JG using algebraic solutions:

Let HJ = y

Based on the altitude theorem, we would have:

y = √(16 × JG)

Substitute

y = √(16 × 9)

y = √(144)
y = 12

Therefore, the length of HJ is: 12.

Learn more about the leg rule on:

brainly.com/question/25016594

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The median income for a sample of people from Chicago is about $60,000 and the

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Rearrange each of the following formula so the pronumeral in the bracket becomes the subject of the equation

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Step-by-step explanation:

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Step-by-step explanation:

inland city has the coldest winter and warmest summer.

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3 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

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3 years ago

A TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 500

nekit [7.7K]

Answer:

0.903264

Step-by-step explanation:

Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.

Let A' = the event that A fails, B' = B fails and C'= C fails.

Probability that no circuit board fails = Prob (A'B'C')

= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent

= (1-0.03)(1-0.04)(1-0.03)

= 0.903264

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