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ira [324]
3 years ago
7

An airplane descends 1.5 miles to an elevation of 5.25 miles. Write and solve an equation to find the elevation of the plane bef

ore its descent.
Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0
2.25 is the elevation of the plane before its decent
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The force F between 2 objects is inversely proportional to the square of the distance, d between them. The force is 0.36 newtons
LenaWriter [7]

Answer:

0.73 N to 2 dp.

Step-by-step explanation:

F = k/d^2   where k is a constant , F = force and d = distance.

Substituting:

0.36 = k / (6)^2

k = 36*0.36 = 12.96 s the equation is F = 12.96 / d^2.

When d = 4.2 :

F = 12.96 / 4.2^2

F = 0.73 Newtons to 2 dp.

5 0
3 years ago
Plzzzz help and I'll give you brainliest ​
sdas [7]

Step-by-step explanation:

Left hand side:

4 [sin⁶ θ + cos⁶ θ]

Rearrange:

4 [(sin² θ)³ + (cos² θ)³]

Factor the sum of cubes:

4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]

Pythagorean identity:

4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]

Complete the square:

4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]

4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]

Pythagorean identity:

4 [1 − 3 sin² θ cos² θ]

Rearrange:

4 − 12 sin² θ cos² θ

4 − 3 (2 sin θ cos θ)²

Double angle formula:

4 − 3 (sin (2θ))²

4 − 3 sin² (2θ)

Finally, apply Pythagorean identity and simplify:

4 − 3 (1 − cos² (2θ))

4 − 3 + 3 cos² (2θ)

1 + 3 cos² (2θ)

3 0
3 years ago
a suit is being sold at a 20 % off (discount). The sale price is $ 270. What was the original price ?
Lisa [10]

Answer:

The original price is 337.50

Step-by-step explanation:

If we get 20% off, we still have to pay 100-20 =80%

Let x be the original price

x *80% = 270

.80x = 270

Divide each side by .80

.80x/.80 = 270/.80

x =337.50

The original price is 337.50

5 0
3 years ago
Read 2 more answers
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
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a car can drive 600 miles on 18 gallons of gasoline. How many miles can a car drive on 15 gallons of gasoline​
PolarNik [594]

Answer:

Use the cross technique if it’s name like that in English but , I wish you can understand it from what I‘ve written .

3 0
2 years ago
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