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2 years ago

5

What is one reaction that will form an arrhenius base?.

1 answer:

maksim [4K]2 years ago

8 0

Answer:

An alkaline solution is another name for a solution that is basic. All alkali metals react readily with water to produce the metal hydroxide and hydrogen gas. The resulting solutions are basic.

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Which of the following best describes how water evaporates? *

Evgesh-ka [11]

The answer is A because water can only evaporate if a liquid substances becomes gas , in this case it’s the water. When water is heated it evaporates. The molecule moves and vibrates so quickly that they can move to the atmosphere

4 0

3 years ago

Suppose 20.23 g of glucose are dissolved in 95.75 g of water at 27.0 OC. Glucose is nonvolatile (has no vapor pressure) and has

leonid [27]

Answer:

Explanation:

From the information given :

we can understand the solute is glucose and the solvent is water,

So, the weight of glucose = 20.23 g

the molecular weight of glucose = 180.2 g/mol

weight of water = 95. 75 g

the molecular weight of water = 18.02 g/mol

pure vapor pressure of water $P_A = 26.7 \ mmHg$ at 27°C

moles of glucose = weight of glucose/ molecular weight of glucose

= 20.23/180.2

= 0.11 mole

moles of water = weight of water / molecular weight of water

= 95.75/18.02

= 5.31 mole

mole fraction of glucose $X_{glucose} =$ (moles of glucose)/(moles of glucose+ moles of water)

$X_{glucose} =$ 0.11/(0.11 + 5.31)

$X_{glucose} =$ 0.0203

mole fraction of glucose $X_{water} =$ (moles of water)/(moles of water+ moles of glucose)

$X_{water} =$ 5.31/ (5.31 + 0.11)

$X_{water} =$ 0.9797

Using Raoult's Law:

$P_S = P^0_A \times X_A \ \ \ OR \ \ \ P_A = P^0_A \times X_A$

where:

$P_S$ = vapor pressure of the solution

$P_A$ = total vapor pressure of the solution

$P^0_A$ = vapor pressure of the solvent in the pure state

$X_A$ = mole fraction of solvent i.e. water

$P_A =$ 95.75 × 0.9797

$P_A =$ 93.81 mmHg

the total vapor pressure of the solution = 93.81 mmHg

4 0

3 years ago

How to find the mole fraction of each gas in the vessel after the reaction

sattari [20]

Do DIMENSIONAL Analysis what comes up must come down

7 0

4 years ago

Calculate the [OH-] and the pH of 0.035 M KOH.

DanielleElmas [232]

Answer:

pH

$= 12.54$

OH- concentration 28.84

Explanation:

KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1

In any aqueous solution, the H3O+ and OH - must satisfy the following condition -

$[ H_3O^+] [OH^-] = k_w$

$[ H_3O^+] = \frac{k_w}{ [OH^-]}$

$[H_3O^+] = \frac{1 * 10^{-14}}{3.5 *10^{-2}[H_3O^+] = 2.857 * 10^{-13}$ M

pH =

$- log [ H_3O^+]\\- log [2.857 * 10^{-13}]$

pH

$= - [-12.54]\\= 12.54$

pOH $= 14 -$ pH

pOH

$= 14 - 12.54\\= 1.46$

OH concentration $= antilog 1.46$

OH- concentration 28.84

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4 years ago

PLEASE HELP, DUE AT 12:00

elena55 [62]

Answer:

<h2>5.C</h2><h2>6.D</h2>

Explanation:

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7 0

3 years ago