Answer:
72.8 % (But verify explanation).
Explanation:
Hello,
In this case, with the following obtained results, the percent error is computed as follows:
Volume of vinegar= 7.0 mL
Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL
Used concentration of NaOH= 1.5M
Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M
Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol
Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g
% of acetic acid in vinegar=8.64 %
% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %
Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.
Regards.
Answer:
y or z one of those two i think its z but im so sorry if im wrong if not z then try y also I learned this last year.
Answer:
isopropanol + oxygen Right arrow. carbon dioxide + water + heat
Explanation:
Word equation:
isopropanol + oxygen → carbon dioxide + water + heat
Chemical equation:
2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O + Heat
The given reaction is combustion of isopropanol. Isopropanol burn in the presence of oxygen and produced carbon dioxide and water. Heat is also produced in this reaction.
The given reaction also follow the law of conservation of mass. There are equal number of moles of each element on both side of reaction equation thus mass remain conserved.
B: Liquid take the shape of their container.
A lot of values are given but we must focus only on HCl.
<span>There are 215 mL (0.215 L) of 0.300 M HCl that was
completely used. We must remember the
moles is simply the product of volume and molarity, that is:</span>
number of moles = 0.215 L * 0.300 M
<span>number of moles= 0.0645 moles HCl</span>
