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seraphim [82]
3 years ago
14

PLEASE HELP, DUE AT 12:00

Chemistry
1 answer:
elena55 [62]3 years ago
7 0

Answer:

<h2>5.C</h2><h2>6.D</h2>

Explanation:

YONG ISA PO ETO HINDI KO PO ALAM TOH

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If an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom what wavelength of light is emitted?
arsen [322]

Answer:

Ultraviolet

Explanation:

It doesn't use much energy and so it creates ultraviolet light.

4 0
3 years ago
Which of the following is NOT possible? a. compressing 10 liters of oxygen gas into a 1-liter volume b. compressing 2 liters of
KonstantinChe [14]

Answer:b

Explanation:

8 0
3 years ago
Read 2 more answers
If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79
Helen [10]
1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu

2) we need to convert the grams of CuSO₄ to moles using the molar mass. 

molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol

200.0 g CuSO_4 ( \frac{1 mol}{160 grams} )= 1.25 mol CuSO_4

3) convert moles of CuSO₄ to moles of Cu

1.25 mol CuSO_4 ( \frac{1 mol Cu}{1 mol CuSO_4} )= 1.25 mol Cu

4) convert moles of Cu to grams using it's molar mass.

molar mass Cu= 63.5 g/mol

1.25 mol (\frac{63.5 grams}{1 mol} )= 79.4 grams Cu

I did it step-by-step as the explanation but you can do all of this in one step. 

200.0 g CuSO_4 ( \frac{1 mol CuSO_4}{160 g} ) ( \frac{1 mol Cu}{1 mol CuSO_4} ) ( \frac{63.5 grams}{1 mol Cu} )= 79.4 grams Cu


4 0
4 years ago
g How many moles of NaOH are present in a sample if it is titrated to its equivalence point with 44.02 mL of 0.0885 M H2SO4? 2Na
Lisa [10]

Answer:

n_{base}=3.90x10^{-3}molNaOH

Explanation:

Hello!

In this case, since the sulfuric acid and sodium hydroxide react in a 1:2 mole ratio, given the reaction, we realize they have the following mole ratio at the equivalence point:

2*n_{acid}=n_{base}

Which in terms of concentrations and volumes is:

2*M_{acid}V_{acid}=n_{base}

Thus, we can plug in the volume and concentration of acid to find the moles of base:

n_{base}=0.04402L*0.0885\frac{mol}{L} \\\\n_{base}=3.90x10^{-3}molNaOH

Best regards!

8 0
3 years ago
38 POINTS IF YOU CAN HELP ME PLEASE PLEASE PLEASEEE
guajiro [1.7K]
Red blood cell is the answer I think
6 0
3 years ago
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