First one:
You take 10 + 3 =13 then add 9 then 5. That all equals 27. Then you add 1 for the top part that isn’t labeled because it’s 10 in the bottom then 9 at the top which means it’s 1. Then for the side that’s unlabeled it’s 2 since it’s all 5 then the other side is 3. Answer is 31
Second one:
This one is the same as #1. You add 14+6+3+4 = 27. The long horizontal unlabeled side is 11 bc 14-3 = 11. Then the other side 2. Answer is 30.
Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>
Step-by-step explanation:
We know

for any real value of <em>a</em>.
|a| = b > 0 - <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 <em>add 4 to both sides</em>
|x + 6| = 9 > 0 <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10 <em>add 4 to both sides</em>
|x + 6| = -6 < 0 <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 <em>subtract 6 from both sides</em>
x = 3 or x = -15
A^2-b^2=(a+b)(a-b)
1: x^2-4=(x+2)(x-2)
2: (x+8)(x-8)
3: (x+10)(x-10)
4: (x+14)(x-14)
Answer: 8 tons
Step-by-step explanation: