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raketka [301]
3 years ago
8

I need help its not that hard please please please!

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
Your right, it's not that hard, sloop read your book!
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Kailee paid $14.84 for stamps. The number of .49-cents stamps was four less then three times the number of 21-cent stamps. How m
Akimi4 [234]

Answer:

Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.

Step-by-step explanation:

Given:

Total Money paid for stamps = $14.84

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Also Let the number of 21-cents stamps be y.

Now Total Money paid is equal to sum of number of 49-cents stamps and number of 21-cents stamps.

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So 49 cents = $0.49

and 21 cents = $0.21

Hence equation be framed as;

0.49x+0.21y =14.84 \ \ \ \ equation \ 1

Also Given:

number of .49-cents stamps was four less then three times the number of 21-cent stamps.

hence we can say that;

x=3y-4\ \ \ \ equation \ 2

Now Substituting the value of equation 2 in equation 1 we get;

0.49(3y-4)+0.21y=14.84\\1.47y- 1.96+0.21y=14.84\\1.68y=14.84+1.96\\1.68y = 16.8\\y=\frac{16.8}{1.68}=10

Now substituting the value of y in equation 2 we get;

x=3y-4\\x=3\times10-4\\x=30-4\\x=26\\

Hence Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.

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3 years ago
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<u><em></em></u>

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3 years ago
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