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raketka [301]
3 years ago
8

I need help its not that hard please please please!

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
Your right, it's not that hard, sloop read your book!
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The first four numbers of a sequence are 3,9,27 and 81. If this sequence continues, what are the next two numbers
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Step-by-step explanation:

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Math riddle!
daser333 [38]

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47

Step-by-step explanation:

There are total 52 cards.

Certain number of cards are lost.

When divided by 4, leaves 3 cards remain ; 51, 47, 43, 39, . . .

When divided by 5, leaves 2 cards remain : 47, 42, 37, 32, . . .

When divided by 3, leaves 2 cars remain : 50, 47, 44, 41, . . .

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The value from the set {10, 11, 12, 13} that makes the equation 2(x − 5) = 12 true is <br>.​
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C :) hope it helps

Step-by-step explanation:

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3 years ago
HELPPPP- you just got your driver's license. Your parents buy you a car and agree to let you pay them back over a period of 70 m
Nitella [24]

Using the monthly payments formula, it is found that a car with a value of at most $25,293.

<h3>What is the monthly payment formula?</h3>

It is given by:

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

In which:

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  • r is the interest rate.
  • n is the number of payments.

In this problem, we have that the parameters are given as follows:

A = 400, n = 70, r = 0.035.

Hence:

r/12 = 0.035/12 = 0.002917.

Then we have to solve for P to find the maximum value of the car.

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

400 = P\frac{0.002917(1.002917)^{70}}{(1.002917)^{70}-1}

P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}

P = $25,293.

More can be learned about the monthly payments formula at brainly.com/question/26267630

#SPJ1

7 0
1 year ago
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