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kolezko [41]
2 years ago
7

Jacob spent half of his weekly allowance at the movies. To earn more money his parents let him wash the car for $7. What is his

weekly allowance (w) if he ended up with $13? The variable should always go in the first term.
Mathematics
1 answer:
sweet [91]2 years ago
5 0

Answer:

6 dollers couse 13 minuse 7 equels to 6

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The answer is the first options: y=-2

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I need help on 19 and 20
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Number 19 you are comparing one measurement to another. Since it says 1/2 inch equals 4 ft, we want to find out how many more inches are needed if the given scale was 2/3 = 4 ft. Now lets find a common denominator for both scales stated in inches. We have 2/3 inch and 1/2 inch. Our denominator are the bottom parts of the fraction where we need to find a common factor for the denominator so we can add or subtract fractions. We have a 3 and a 2. You may always use the multiplication between two denominators to find a common factor such as 3 times 2 which equals 6 for both denominators. Now we multiplied the 3 by 2 to get 6 so the top part (numerator needs to be multiplied the the 2 because we changed the bottom part by 2 as well. You should notice that when you reduce your fraction now 4/6 is 2/3. Just a self check example there. As for 1/2 we multiplied a 3 to get 6 for the denominator so we need to multiply the numerator by 3 as well. You now should have 4/6 and 3/6. Since the question asks for how many more inches we need to subtract 4/6 from 3/6 and we get 1/6 inch for our answer.
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3 years ago
A jewelry store offers its own brand of customizable charm bracelets. You are able to choose from 9
Elis [28]

Answer:

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4 0
3 years ago
A square pyramid has side lengths each measuring 8 centimeters. The height of the pyramid is 3 centimeters,
tino4ka555 [31]
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3 years ago
Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

3 0
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