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Elodia [21]
2 years ago
14

What is line PR called​

Mathematics
2 answers:
rodikova [14]2 years ago
7 0

Answer:

A radius is a line segment with one endpoint at the center of the circle and the ... is called the midpoint, and arc PQ ≅ arc PR if and only if PQ ≅ PR.

Step-by-step explanation:

brainliest please

mario62 [17]2 years ago
5 0

Answer:

A radius is a line segment with

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Help this is for integers haha
OverLord2011 [107]
Idk but give me brainliest it will give you points back
7 0
3 years ago
How to find the height of a 30-60-90 triangle with hypotenuse = 8, and base = 8sqrt.3. Please help find answer fast!
Daniel [21]
For a 30-60-90 triangle
if the shorter leg (oposite 30 degrees) is x then the other leg is x√3 and the hyptonuse is 2x

so
hyptonuse=8
8=2x
4=x

longer leg is 4√3, yep
so shorter leg or height will be 4 units
5 0
2 years ago
#10: find angle x and y!<br> Im struggling so much with this question please help a gurl out!
hjlf

Answers:

x = 100

y = 25

==============================================================

Explanation:

Angle y and the 25 degree angle are corresponding angle. Because the lines are parallel, this means that y = 25

Check out the attached image. Using a red pen, I extended one of the lines to form a triangle. From the alternate interior angle theorem, we know that one of the angles of the triangle is 75 degrees (alternate interior angles are congruent). Again this stems from the fact that the lines are parallel.

I've also introduced the variable z to help find x. The angles x and z add up to 180 degrees since they form a straight line. So we need to find z before we can find x.

The triangle's angles 25, 75, z add up to 180. Let's solve for z

25+75+z = 180

100+z = 180

z = 180-100

z = 80

Use this to find x

x+z = 180

x+80 = 180

x = 180-80

x = 100

4 0
2 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
I've literally asked this question 5 times lol. Can someone please help me?
Tju [1.3M]
I think i know the answer to that question. just wait for a sec.
6 0
2 years ago
Read 2 more answers
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