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Ivanshal [37]
3 years ago
5

The driver of a car traveling at 54ft/sec suddenly applies the brakes. The position of the car is s=54t-3t^2, t seconds afyer th

e driver applies the brakes.
How many seconds after the driver applies the brakes does the car come to a stop
Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
  <span>s = 60t - 3t^2 
v = ds/dt = 60 - 6t 

when it comes to rest, v = 0, 
so t = 10 sec 

now distance travelled = time taken x average velocity 
= 10 x (60 + 0)/2 
= 300 ft 

</span>
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