<u>Answer:</u>
Perimeter = 20 units
x = 120°
<u>Step-by-step explanation:</u>
We are given a triangle ABC with known side lengths for all three sides and an inscribed circle.
We are to find the perimeter of triangle ABC and the value of x.
Perimeter of triangle ABC = 2 + 2 + 5 + 5 + 3 + 3 = 20 units
The kite shape at the end is a quadrilateral which has a sum of angles of 360 degrees.
Two out of four angles are right angles and one is 60 so we can find the value of x.
x = 360 - (90 + 90 + 60) = 120°
Answer:
C
Step-by-step explanation:
Hope this helps <3
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For the first problem the answer is -5/2
2x−7+10=−2
Step 1: Simplify both sides of the equation.
2x−7+10=−2
2x+−7+10=−2
(2x)+(−7+10)=−2
(Combine Like Terms)
2x+3=−2
Step 2: Subtract 3 from both sides.
2x+3−3=−2−3
2x=−5
Step 3: Divide both sides by 2.
2x/2=−5/2
x=−5/2
Answer:
x= -5/2
X= 2/3
6x/x-6 - 4/x - 24 / x^2 - 6x = 0
6x^2 -4 (x-6)-24 / x(x-6) = 0
6x^2 -4x+ 24 -24/x(x-6) = 0
X(6x-4) / x(x-6)
6x-4/x-5 = 0
6x-4= 0
6x = 4 divide both sides by 6
X= 2/3
I’m here to help.
For this question here you need to use the sine formula for the area of a triangle and figure out the area of the sector
I’ll take you through it step-by-step
Area of the arc:
We only have 68.9 degrees out of 360 and we need to use the formula for the area of a circle.
Formula of a circle = pi x radius squared
68.9/360 x pi x 86.1184= 51.78 (2dp)
Area of triangle:
As you can see we have no height so we must use the sine formula for the area of a triangle.
Formula= 1/2abSinC
You should end up with
0.5 x 9.28x 9.28 x Sin(68.9)= 40.17 (2dp)
Now since you want the area of the segment shaded, just find the difference between these two values.
51.78-40.17 = 11.61
Answer= 11.6cm squared
Hope this helped!
