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Leviafan [203]
2 years ago
5

A film ends at 1.05 a.m and lasts for 1 hour 45 min. At what time does the film start?

Mathematics
2 answers:
Ad libitum [116K]2 years ago
6 0

u will have to add the two

1hr 45mins + 1:05

remember add hrs to hrs and minutes to minutes

1+1 =2

45+5=50

which means the movie started at 2:50 am

and to verify ur answer subtract 2:50 from 1:05

= 1hrs 45 mins

<em>Answer</em><em>=</em><em> </em><em>2</em><em>:</em><em>5</em><em>0</em><em> </em><em>am</em><em> </em>

Dimas [21]2 years ago
3 0

▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

According to above statement, the film started 1 hour and 45 minutes before 1 : 05 am

so, starting time is equal to :

  • 1 hour 45 minutes before 1 : 05

  • 1 : 05 - 1 hour 45 minutes

that is :

  • 11 : 20 pm
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The product of two consecutive integers is 5 more than three time the larger. What are the integers?
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When calculating consecutive integers, the smaller number is x and the larger number is (x + 1).
So the equation you can use is x + (x + 1) = 5 + 3(x + 1)
This is because the sum of the consecutive integers are equal to 5 more than 3 times the larger integer.
Now simplify:
x + (x + 1) = 5 + 3(x + 1)
2x + 1 = 5 + 3(x + 1)
2x + 1 = 5 + 3x + 3
2x + 1 = 3x + 8
Now isolate the variable:
2x + 1 = 3x + 8
Subtract 2x from both sides:
1 = x + 8
Subtract 8 from both side:
-7 = x
x = -7
So the smaller number is -7 and the larger number is -6.

Now check your answer:
-7 + (-7 + 1) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 - 6 = 5 + 3(-7 + 1)
-13 = 5 + 3(-7 + 1)
-13 = 5 + 3(-6)
-13 = 5 + (-18)
-13 = 5 - 18
-13 = -13
This works!

So the integers are -7 and -6.
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