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Leviafan [203]
2 years ago
5

A film ends at 1.05 a.m and lasts for 1 hour 45 min. At what time does the film start?

Mathematics
2 answers:
Ad libitum [116K]2 years ago
6 0

u will have to add the two

1hr 45mins + 1:05

remember add hrs to hrs and minutes to minutes

1+1 =2

45+5=50

which means the movie started at 2:50 am

and to verify ur answer subtract 2:50 from 1:05

= 1hrs 45 mins

<em>Answer</em><em>=</em><em> </em><em>2</em><em>:</em><em>5</em><em>0</em><em> </em><em>am</em><em> </em>

Dimas [21]2 years ago
3 0

▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

According to above statement, the film started 1 hour and 45 minutes before 1 : 05 am

so, starting time is equal to :

  • 1 hour 45 minutes before 1 : 05

  • 1 : 05 - 1 hour 45 minutes

that is :

  • 11 : 20 pm
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Dahasolnce [82]

Answer:

the answer for this question 1200

Step-by-step explanation:

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2 years ago
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Seven hamburgers and four sodas cost $27.35. Four hamburgers and five sodas cost $18.75
Doss [256]

Answer:

equations:

7x + 4y = 27.35

4x + 5y = 18.75

Step-by-step explanation:

x = burgers

y = sodas

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7x + 4y = 27.35

4x + 5y = 18.75

5 0
2 years ago
Determine if the given mapping phi is a homomorphism on the given groups. If so, identify its kernel and whether or not the mapp
shtirl [24]

Answer:

(a) No. (b)Yes. (c)Yes. (d)Yes.

Step-by-step explanation:

(a) If \phi: G \longrightarrow G is an homomorphism, then it must hold

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but the last statement is true if and only if G is abelian.

(b) Since G is abelian, it holds that

\phi(a)\phi(b)=a^nb^n=(ab)^{n}=\phi(ab)

which tells us that \phi is a homorphism. The kernel of \phi

is the set of elements g in G such that g^{n}=1. However,

\phi is not necessarily 1-1 or onto, if G=\mathbb{Z}_6 and

n=3, we have

kern(\phi)=\{0,2,4\} \quad \text{and} \quad\\\\Im(\phi)=\{0,3\}

(c) If z_1,z_2 \in \mathbb{C}^{\times} remeber that

|z_1 \cdot z_2|=|z_1|\cdot|z_2|, which tells us that \phi is a

homomorphism. In this case

kern(\phi)=\{\quad z\in\mathbb{C} \quad | \quad |z|=1 \}, if we write a

complex number as z=x+iy, then |z|=x^2+y^2, which tells

us that kern(\phi) is the unit circle. Moreover, since

kern(\phi) \neq \{1\} the mapping is not 1-1, also if we take a negative

real number, it is not in the image of \phi, which tells us that

\phi is not surjective.

(d) Remember that e^{ix}=\cos(x)+i\sin(x), using this, it holds that

\phi(x+y)=e^{i(x+y)}=e^{ix}e^{iy}=\phi(x)\phi(x)

which tells us that \phi is a homomorphism. By computing we see

that  kern(\phi)=\{2 \pi n| \quad n \in \mathbb{Z} \} and

Im(\phi) is the unit circle, hence \phi is neither injective nor

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7 0
3 years ago
In a certain city, 80 percent of the households have cable television and 60 percent of the households have videocassette record
alexandr1967 [171]

Answer:

60,000

Step-by-step explanation:

Let the total people in the household be 100%

If 80 percent of the households have cable television, 60 percent of the households have videocassette recorders and the number of households that have both cable television and videocassette recorders is 'x' percent. The number of households having ONLY cable television will be 80-x while households having ONLY videocassette will be 60-x.

To get x, we will have;

80-x + 60-x + x = 100

140-x = 100

x = 140-100

x = 40

This shows that 40% of the households have both cable television and videocassette.

If there are 150,000 households in the city, then the number of households that have both cable television and videocassette recorders could be 40% of 150,000

= 40/100 × 150,000

= 60,000

Number of households that owns both television and videocassette could be from 60,000.

3 0
3 years ago
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Afina-wow [57]

Answer:

"101" seems to the appropriate response. The further explanation is provided below.

Step-by-step explanation:

The given expression is:

⇒ (7\times 6 )+(8\times 8)-5

On solving the brackets, we get

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On applying addition, we get

⇒ 106-5

On applying subtraction, we get

⇒ 101

3 0
2 years ago
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