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podryga [215]
3 years ago
9

A newly discovered disease features DNA methylation at cytosines outside of the CpG context. Which cells were most likely involv

ed in this disease process
Biology
1 answer:
il63 [147K]3 years ago
3 0

The cells that were most likely involved in this disease process are Embryonic Stem Cells (ESCs). These cells are pluripotent cells.

<h3>Embryonic Stem Cells, methylation and epigenetics</h3>

Embryonic Stem Cells (ESCs) are pluripotent cells derived from the inner cell mass of the blastocyst.

Conversely, the term 'epigenetics' refers to gene expression mechanisms that do not involve a change in nucleotide sequence.

DNA methylation is an epigenetic mark that happens at the cytosines outside of CpG context in ESC cells.

Learn more about epigenetics here:

brainly.com/question/25681154

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All living things need energy; it is a requirement for life. In a typical cell, ATP, the high energy molecule, is produced in the MITOCHONDRIA <span>in the presence of a sugar (glucose) and OXYGEN.

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3 years ago
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Cytosine guanine thymine and adenine are referred to as phosphates. True or False
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Answer:

False

Explanation:

Cytosine, guanine, thymine, and adenine are collectively referred to as nitrogenous bases. These are not phosphates. The cytosine, guanine, thymine, and adenine are the four different types of nitrogenous bases. These nitrogenous bases are present in the deoxyribonucleotides. Cytosine and thymine are smaller in structure and have single ring structures. These are collectively called pyrimidines. On the other hand, adenine and guanine are the larger nitrogenous bases each with double ring structures. They are collectively called purines

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3 years ago
8. What are the three most important organs in the excretory system?
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Kidneys, ureters and bladder

6 0
3 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
3 years ago
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just olya [345]

Answer:

Most biomolecules are organic compounds, and just four elements—oxygen, carbon, hydrogen, and nitrogen—make up 96% of the human body's mass. But many other elements, such as the various biometals, are present in small amounts.                   Sometimes polymers are also known as macromolecules or large-sized molecules. Usually, polymers are organic (but not necessarily). A monomer is a molecule that is able to bond in long chains.

Explanation:

Understand?

8 0
3 years ago
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