The symbol for a radioactive nuclide is superscript 131 subscript 56 upper b a.. which statement is correct? the atomic number o
1 answer:
In a given radioactive nuclide, we can easily find the mass number, mass of proton and neutron by subtracting the mass of proton from the mass number. The mass number, mass of proton and mass of neutron of the radioactive nuclide are 131, 56 and 75 respectively.
<h3>Properties of an atom</h3>Data;
- Mass Number = 131
- Atomic Number = 56
In a given atom, the mass number of an atom comprises of the mass of proton and mass of neutron. The atomic number of the element or atom is equal to the mass of the proton.
In this case,
mass number = mass of proton + mass of neutron.
From the calculation above, the mass number, mass of proton and mass of neutron of the radioactive nuclide are 131, 56 and 75 respectively.
Learn more on mass of an element here;
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Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y
(a) f:R----> + R given by f(x) = x2 (i guess you written )
The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and is always a positive real number.
(b) f:N----> + N given by f(n) = n2 (i guess you written )
As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.
(c) f: Zx Z → Z given by f(n, k) = n +k:
here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.
Given parameters:
Number of boxes Athena bought for the party = x
Number of cookies per box = 10
Number of cookies she brought to the party = 70
Number removed = 2 boxes
Unknown:
Equation of the number of boxes = ?
Solution:
1 box of cookies contains 10 cookies
If Athena, removed 2 boxes, in those two boxes, we have 20 cookies
Total number of cookies = 70 + 20 = 90 cookies;
So;
x =
Therefore;
x = boxes