F''(x) = 6x + 8
∫f''(x) = f'(x) = 3x^2 + 8x + c1
∫f'(x) = f(x) = x^3 + 4x^2 + c1x + c2
At point (0, -2),
c2 = -2
3x - y = 2
y = 3x - 3
f'(0) = 3
c1 = 3
Therefore, the required function is
f(x) = x^3 + 4x^2 + 3x - 2
Answer:
3
Step-by-step explanation:
the equation is:
y=1/4x+3
Answer:
= - 12 + 316 i
Step-by-step explanation:
Given that -
z = 3 + i
<em>
= 
</em>
<em> = 9 + 
+ 6 i</em>
<em> = 9 - 1 + 6 i</em>
= 8 + 6 i
<em>
= × z</em>
<em> = ( 8 + 6 i ) × ( 3 + i )</em>
<em> = 24 + 8 i + 18 i + 6 i²</em>
<em> = 24 + 26 i - 6</em>
= 18 + 26 i
= ×
<em> = ( 8 + 6 i ) × ( 18 + 26 i )</em>
<em> = 144 + 208 i + 108 i + 156 i²</em>
<em> = 144 + 316 i -156</em>
= - 12 + 316 i
I’m timed on this I need help as well
Answer:
y = -x - 4
Step-by-step explanation:
First find the slope
y - 4 = (x - 6)
y - 4 = x - 6
y = x - 6 + 4
y = x - 2 (y = mx + C)
Slope m = 1
It is said that the line is perpendicular to a point ( -2, -2)
If two lines are perpendicular, their slope will be negative reciprocal
The negative reciprocal of slope = 1 is -1
Using a slope intercept form as requested by the question
y = mx + C
Inserting the values given
(-2, -2)
We are using point slope form
y - y_1 = m ( x - x_1)
x_1 = -2
y_1 = -2
m = -1
Insert the values
y - ( -2)) = -1( x - (-2))
y + 2 = -1 ( x + 2)---- point slope form
But we are requested to give the answer in slope intercept form
y = mx + C
We have to open the bracket
y + 2 = -1(x + 2)
y + 2 = -x - 2
y = -x - 2 - 2
y = -x - 4 ( slope - intercept form)
