Question

What is the slope of the line that contains these point? (13,11),(14,6),(15,1),(16,-4)

Answer 1

Answer:

Slope (m) = -5

Step-by-step explanation:

*If all the given four points are on a straight line then; the slope derived from first two points should be equal to the slope derived from the next to points.

Let's verify this ...

For the first two points:

Slope (m) = change in y ÷ change in x = $\frac{6 - 11}{14 - 13} = \frac{-5}{1} = -5$

For the next two points:

m = $\frac{-4 - 1}{16 - 15} = -5$

*Proved ∴ points (13,11) , (14,6) , (15, 1) and (16,-4) are on the same line.

• We can find the equation of this line and ascertain that the four points are on a single line.

Taking another point (x,y) on the line and point (13,11);

m = $\frac{y - 11}{x - 13} = -5$

y = -5x + 65 + 11

y = -5x + 76

• Let's graph this equation. (graph attached)

Answer 2

Answer:

Step-by-step explanation:

You can easily find the slope by using two points. Let’s use (13, 11) and (14, 6)

We look at the slope equation as: y2 - y1 divided by x2 and x1.

13 = x1 11= y1 and 14= x2 6=y2

Plug in: 6-11/14-13 and solve

Answer: -5

Hope I made sense :)