14a^2bc^4/21abc^6 = 2a/3b^2
Hope this helps :))
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Let's draw the diagonals of the square. The square is being divided by 4 right triangles. & these right triangles are also isosceles (the diagonals of a square intercepts each other in the middle).
The area of each right triangle = (6 x 6) / 2 = 18 yard² & the 4 right triangles => 4x 18 = 72 yd²
Can’t see the other graphs but C or D, the one most similar to A