Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).
Taking 2x is power of 3.
So it will be like 3^(2*1/2) + 1
You are replacing 'x' with 1/2
and the equation becomes 3^1+1
So, f(1/2) = 4
Answer is 4.
If its like
<span>3^(2x+1)
Then its like 3^[(2*1/2) +1]
It becomes 3^(1+1) = 3^2 = 9
So, the answer is 9
</span>
Both 27 and 45 have the greatest common factor of 9, so divide the numerator and the denominator by 9 to get the simplest form.
27/45 = 3/5
3/5 is the simplest ratio
Answer:
5
Step-by-step explanation:
x^2 - 10x + 16 = 0
factor
(x - 2)(x - 8) = 0
roots
x = {2, 8}
mean of roots
a = (2 + 8) /2
a = 5
Answer:
the anwsere is d>?
Step-by-step explanation:
