Answer:
Next time show a picture
Step-by-step explanation:
But! A way you could solve this is to look at the opposite angle of 1 and see what the number is. The number opposite of 1 is always equal to 1. You could also see if there is a number next to 1. The number next to 1 +1= 180 degrees. Good luck!
Answer:
Jiri is 38 years old.
Step-by-step explanation:
First, 67 - 29 = 38 and 29 + 9 = 38.
Hope this helps!
Answer:
A. 2/3
Opposite Sides of a Parallelogram
The two pairs of sides in a parallelogram are parallel to each other.
Parallel lines have the same slope.
The slope of the opposite sides of a parallelogram are congruent (equal in measure).
Given:
Slope of PQ = 2/3
Slope of QR = -1/2
For PQRS to be a parallelogram, the slope of SR must be same as the slope of PQ.
This implies that: Slope of SR = Slope of PQ = 2/3.
Therefore, based on the properties of a parallelogram, the slope of SR for PQRS to be a parallelogram would be: 2/3.
Answer:
The answer to your question is (2)(3)(11)
Step-by-step explanation:
Data
154
Process
1.- Find the prime factors of 154, starting with 2, then, 3, 5, 7, etc
154 2
77 7
11 11
1
2.- Write 154 as a composition of prime factors
154 = (2)(7)(11)
3.- Conclusion
The prime factors of 154 are 2, 3 and 11
Answer:
(x + 6, y + 0), 180° rotation, reflection over the x‐axis
Step-by-step explanation:
The answer can be found out simply , a trapezoid has its horizontal sides usually parallel meanwhile the vertical sides are not parallel.
The horizontal parallel sides are on the x-axis.
Reflection over y- axis would leave the trapezoid in a vertical position such that the trapezoid ABCD won't be carried on the transformed trapezoid as shown in figure.
So option 1 and 2 are removed.
Now, a 90 degree rotation would leave the trapezoid in a vertical position again so its not suitable again.
In,The final option (x + 6, y + 0), 180° rotation, reflection over the x‐axis, x+6 would allow the parallel sides to increase in value hence the trapezoid would increase in size,
180 degree rotation would leave the trapezoid in an opposite position and reflection over x-axis would bring it below the Original trapezoid. Hence, transformed trapezoid A`B`C`D` would carry original trapezoid ABCD onto itself