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Nadusha1986 [10]
3 years ago
11

If x + 2 is a factor of x^3 - 2ax^2 +16, then value of a is i) 3 ii) 1 iii) 4

Mathematics
2 answers:
morpeh [17]3 years ago
7 0

Answer:

ii) 1

Step-by-step explanation:

Let p(x) = x^3-2ax^2+16

<u><em>Given that x+2 = 0 </em></u>

Then => x = -2

Putting this in p(x)

p(-2) = (-2)^3-2a(-2)^2+16

<u><em>By remainder theorem , Remainder will be zero</em></u>

0 = -8-8a+16

0 = -8a+8

-8a = -8

<em>Dividing both sides by -8</em>

<em>=> </em><em>a = 1</em>

grandymaker [24]3 years ago
3 0

Answer:

a=1 is the answer

Step-by-step explanation:

let

p(x)=x³-2ax²+16

put x= -2

p(-2)=(-2)³-2a(-2)²+16

p(-2)=-8+16-8a

p(-2)=8-8a

as (x+2) is a factor of p(x) then p(x) is equal to zero

8-8a=0

8=8a

a=1

i hope this will help you

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