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borishaifa [10]
3 years ago
7

What is the surface area of the box if it is scaled up by the factor of 10 and the surface area is 16in

Mathematics
1 answer:
algol [13]3 years ago
3 0
If each linear dimension is scaled by a factor of 10, then the area is scaled by a factor of 100. This is because 10^2 = 10*10 = 100. Consider a 3x3 square with area of 9. If we scaled the square by a linear factor of 10 then it's now a 30x30 square with area 900. The ratio of those two areas is 900/9 = 100. This example shows how the area is 100 times larger.

Going back to the problem at hand, we have the initial surface area of 16 square inches. The box is scaled up so that each dimension is 10 times larger, so the new surface area is 100 times what it used to be

New surface area = 100*(old surface area)
new surface area = 100*16
new surface area = 1600

Final Answer: 1600 square inches

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401.92u^3

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Y/20=x <br> I need help on how to solve and the answer!
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12

Step-by-step explanation:

6 0
3 years ago
5x-2y=30 complete the missing value in the solution to the question (8, )
natali 33 [55]

Answer:

(8,5)

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5x-2y=30

lets substitute "8" as x and see where that takes us

5(8)-2y=30

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4 0
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Read 2 more answers
Find all points on the circle (x^2) + (y^2) = 676 where the slope is 5/12
borishaifa [10]
Implicit defferentation

remember that dy/dx y= dy/dx


so
take derivitive of both sides
2x+2y \space\ \frac{dy}{dx}=0
solve for \frac{dy}{dx}
minus 2x both sides
2y \space\ \frac{dy}{dx}=-2x
divide both sides by 2y
\frac{dy}{dx}=\frac{-2x}{2y}
\frac{dy}{dx}=\frac{-x}{y}

when is the slope equal to \frac{5}{12}
solve for \frac{dy}{dx}=\frac{5}{12}
\frac{dy}{dx}=\frac{5}{12}
\frac{5}{12}=\frac{-x}{y}
5y=-12x
y=\frac{-12}{5}x
find where the circle and this line intersects

substitute \frac{-12}{5}x for y
x^2+(\frac{-12}{5}x)^2=676
x^2+\frac{144}{25}x^2=676
\frac{25}{25}x^2+\frac{144}{25}x^2=676
\frac{169}{25}x^2=676
times both sides by \frac{25}{169}
x^2=100
sqrt both sides, take positive and negative roots
x=+/-10

sub back

y=\frac{-12}{5}x
y=(\frac{-12}{5})(10) \space\ or \space\ (\frac{-12}{5})(-10)
y=\frac{-120}{5} \space\ or \space\ \frac{120}{5}
y=-24 \space\ or \space\ 24

the points are (10,-24) and (-10,24)
8 0
3 years ago
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