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4 years ago

2x-2y=6;3x+2y=9 Solve for systems of equations

Mathematics

1 answer:

tensa zangetsu [6.8K]4 years ago

7 0

Answer:

x=3

Step-by-step explanation:

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Write the ratio two fifths<br> to 8 as a fraction in simplest form.<br><br> PLEASE HELP

charle [14.2K]

Answer:

the answer is b on oddesseyware

Step-by-step explanation:

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4 years ago

What is the value of ( 2 1/4 ) ?

castortr0y [4]

Answer:

2.25

Step-by-step explanation:

1/4 (one quarter) is equal to .25 or 25% of 100

2+.25=2.25

3 0

3 years ago

Help me how to simplify this steps by steps, please

Sliva [168]

Sqrt 80n^2 = sqrt 40x2xnxn = sqrt 20x2x2xnxn = sqrt 10x2x2x2xnxn = sqrt 5x2x2x2x2xnxn

Pull out numbers and letters in groups of 2

2x sqrt 5x2x2xnxn
2x2x sqrt 5xnxn
2x2xnx sqrt 5

Multiply the numbers and letters on the outside of the radical

4n x sqrt 5 is the final answer.

8 0

4 years ago

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-Dominant- [34]

Answer:

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Step-by-step explanation:

6 0

4 years ago

What is the decibel level of a dog barking with intensity 10−5 watts per square inch? Use a logarithmic model to solve.

Vsevolod [243]

Answer:

The sound intensity is about 101.9 dB

Step-by-step explanation:

Sound intensity is the amount of sound energy per unit area.

The intensity of the dog bark is 10⁻⁵ W/in². The intensity of sound in decibels is given by:

$\beta=10\ dB*log(\frac{I}{I_o} )\\\\Where\ I=Sound\ intensity\ in \ W/m^2, I_o=reference\ sound\ intensity=10^{-12}\ W/m^2\, \beta= sound\ intensity\ in\ dB$

I = 10⁻⁵ W/in² = 0.0155 W/m²

Therefore:

$\beta=10\ dB*log(\frac{I}{I_o} )\\\\\beta=10\ dB*log(\frac{0.0155}{10^{-12}} )\\\\\beta=101.9\ dB$

The sound intensity is about 101.9 dB

5 0

3 years ago