Question

Determine the equation of the circle with center (0,6) containing the point (74,2)

Answer 1

The circle with center (0,6) containing the point (74,2) has an equation of x² + (y - 6)² = 74.1²

How to calculate the equation of a circle

The equation of a circle is:

(x - h)² + (y - k)² = r²

Where (h, k) is the center and r is the radius.

The circle with center (0,6) containing the point (74,2). Hence:

$Radius=\sqrt{(2-6)^2+(74 -0)^2}=74.1\ unit$

The equation is:

x² + (y - 6)² = 74.1²

Find out more on circle at: brainly.com/question/24375372