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Phoenix [80]
2 years ago
6

HELP QUICK!! ASAP! I NEED HELP ON THIS EQUATION. I WILL MAKE BRAINLIST ​

Mathematics
1 answer:
vladimir1956 [14]2 years ago
8 0
Answer:
4

Explanation:
I’ve attached my work
Hope it helps, Let me know if you have anymore questions/concerns !
Have a nice rest of your day :)

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Ruby works in a bike shop where she makes repairs. She needs to order tires for bikes and quads, which have different kinds of t
valkas [14]

Each bike has two tires, while each quad has four tires. Therefore the number of tires Ruby has to other is given by the number of tires used by the bikes added by the number of tires used by the quads. This is shown on the expression below:

\text{tires}=2\cdot b+4\cdot q

5 0
11 months ago
.08 is 10 times as much as
Mazyrski [523]
It is 10 times as much as .008

Do you see the pattern?
5 0
3 years ago
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
Can someone help.
r-ruslan [8.4K]

Answer:

m∠C = 38°  (nearest whole number).

Step-by-step explanation:

To find the missing angle, use the Sine Rule.

<u>Sine Rule</u> (for angles)

\sf \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

where:

  • A, B and C are the angles
  • a, b and c are the sides opposite the angles

Given:

  • A = 53°
  • a = 18
  • c = 14

To find m∠C, substitute the given values into the formula and solve for C:

\implies \sf \dfrac{\sin 53^{\circ}}{18}=\dfrac{\sin C}{14}

\implies \sf \sin C= \dfrac{14 \sin 53^{\circ}}{18}

\implies \sf C= \sin^{-1} \left( \dfrac{14 \sin 53^{\circ}}{18}\right)

\implies \sf C= 38.40096301...^{\circ}

Therefore, m∠C = 38°  (nearest whole number).

Learn more about the sine rule here:

brainly.com/question/27089170

brainly.com/question/27704834

5 0
2 years ago
Pls help 20 points and mark brainliest
tatiyna
1:equilateral
2:isosceles
3:scalene
4:right
5:acute
6:obtuse
8 0
3 years ago
Read 2 more answers
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