The prediction for the number of passwords in which the first character is a vowel is 56 passwords.
<h3>How to find that a given condition can be modelled by binomial distribution?</h3>
Binomial distributions consist of n independent Bernoulli trials.
Bernoulli trials are those trials which end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))
Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as
![X \sim B(n,p)](https://tex.z-dn.net/?f=X%20%5Csim%20B%28n%2Cp%29)
The probability that out of n trials, there'd be x successes is given by
![P(X =x) = \: ^nC_xp^x(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3Dx%29%20%3D%20%5C%3A%20%5EnC_xp%5Ex%281-p%29%5E%7Bn-x%7D)
The expected value and variance of X are:
![E(X) = np\\](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np%5C%5C)
Given that the characters that can be used are numbers 0 through 9 and lowercase letters. Therefore, a total of 36 different characters are available.
Since we need to know the passwords made with vowels, therefore, the probability of a password in which the first character will be a, e, i, o, u is (5/36).
Now as the computer produces 400 passwords, therefore, the predicted value can be written as,
![E = np = 400 \times \dfrac{5}{36} = 55.5556 \approx 56](https://tex.z-dn.net/?f=E%20%3D%20np%20%3D%20400%20%5Ctimes%20%5Cdfrac%7B5%7D%7B36%7D%20%3D%2055.5556%20%5Capprox%2056)
Hence, the prediction for the number of passwords in which the first character is a vowel is 56 passwords.
Learn more about Binomial Distribution:
brainly.com/question/14565246
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