The population density in the United States is D = 92.1 people/mi^2
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How to get the population density?</h3>
To get the population density, we need to take the quotient between the total number of people and the area.
In this case, we know that the total population is 325.7 million, and the area of the United States is 3,535,932 mi^2
Then the population density:
D = (325.7 million)/( 3,535,932 mi^2) = 9.21*10⁻⁵ million/mi^2
And we know that 1 million = 1,000,000 = 1*10⁶
Then:
9.21*10⁻⁵ million/mi^2 = 9.21*10¹ people/mi^2 = 92.1 people/mi^2
This means that in each square mile in the United States, there are around 92.1 people.
If you want to learn more about density:
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Answer:
x ≈ {-2.80176, -0.339837}
Step-by-step explanation:
Write in terms of sine and cosine:
sec(x) -5tan(x) -3cos(x) = 0 . . . . . . given, subtract 3cos(x)
1/cos(x) -5sin(x)/cos(x) -3cos(x) = 0
Multiply by cos(x). (Note, cos(x) ≠ 0.)
1 -5sin(x) -3cos(x)² = 0
Use the trig identity to write in terms of sin(x).
1 -5sin(x) -3(1 -sin²(x)) = 0
3sin(x)² -5sin(x) -2 = 0 . . . . . . . . quadratic in sin(x)
(sin(x) -2)(3sin(x) +1) = 0 . . . . . . factor the quadratic
Values of sin(x) that make this true are ...
sin(x) = 2 . . . . . true only for complex values of x
sin(x) = -1/3
Then the possible values of x are ...
x = arcsin(-1/3), -π -arcsin(-1/3)
x ≈ {-2.80176, -0.339837} . . . . . rounded to 6 sf