The absolute maximum of a continuous function $f(x)$ is where $f'(x)=0$ . Therefore, we must differentiate the function and then set $x=-5$ and $f'(x)=0$ to determine the value of $c$ :

$f(x)=xe^{-x}+ce^{-x}$

$f'(x)=-xe^{-x}+e^{-x}-ce^{-x}$

$0=-(-5)e^{-(-5)}+e^{-(-5)}-ce^{-(-5)}$

$0=5e^{5}+e^{5}-ce^{5}$

$0=e^5(5+1-c)$

$0=6-c$

$c=6$

Therefore, when $c=6$ , the absolute maximum of the function is $x=-5$ .

I've attached a graph to help you visually see this.

7 0

3 years ago

Name this angle X Х 4 Y N

Katyanochek1 [597]

Answer:

no I have no answer

Step-by-step explanation:

noooooooooooooo

4 0

3 years ago

Simplify the following expression.

son4ous [18]

Answer:

C. log 9

Step-by-step explanation:

Hope this helped!

6 0

3 years ago

The easiest way to find THE SLOPE on a graph? Please HELP

ratelena [41]

Step-by-step explanation:

Pick two points on the line and determine their coordinates

Select one to be (x1, y1) and the other to be (x2, y2)

Finally use the slope intersect equation to calculate the slope:

Formula-

y = mx + b

Hope this helps, let me know if you need more information, I'll be glad to help! :)

3 0

3 years ago