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Darina [25.2K]
2 years ago
9

What set of numbers are shaded on the

Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0

Answer:

looks like you forgot to attach the image to show the values

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There are 40 GT students going on a field trip. Each one pays their teacher $8.75 to cover admission to the museum and lunch. Ad
Norma-Jean [14]

Step-by-step explanation:

There are 40 DuBois students going on a field trip.

Each one pays their teacher $8.75 to cover admission to the museum and lunch.

Admission for the students is $120 and each one gets an equal amount to spend on lunch.

To Find :

How much will each DuBois student be able to spend on lunch.

Solution :

Amount they paid for admission :

\begin{gathered}P =\$ \dfrac{120}{40}\\\\P=\$3\end{gathered}P=$40120P=$3

Now, amount of money to spend on lunch is 8.75 -8.75−3 = $5.75 .

Hence, this is the required solution.

3 0
3 years ago
How much would the account earn in 1 year of simple interest at a yearly rate of 2.33%? Round to the nearest cent.
serg [7]

Answer:

who knows what is the whole question

Step-by-step explanation:

3 0
3 years ago
Which function is graphed below?<br> f(x) = -cos(x)<br> f(x) = cos(x)<br> fx) = sin(x)
andrey2020 [161]

Answer:

cos(x)

Step-by-step explanation:

.

4 0
3 years ago
Hello i need some help
Natalija [7]

Answer:

y = 2x - 1

Step-by-step explanation:

(3, 5) (5, 9)

slope = (9-5)/(5-3) = 4/2 = 2

y = mx + b

5 = 2(3) + b

-1 = b

y = 2x -1

6 0
3 years ago
Read 2 more answers
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
3 years ago
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