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Lera25 [3.4K]
3 years ago
6

If I fail this I fail the quarter. please help appreciate it

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0
C causw it is used to be a difrent cuase it just is

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Help! please i cant figure it out.
ki77a [65]

let's recall that the graph of a function passes the "vertical line test", however, that's not guarantee that its inverse will also be a function.

A function that has an inverse expression that is also a function, must be a one-to-one function, and thus it must not only pass the vertical line test, but also the horizontal line test.

Check the picture below, the left-side shows the function looping through up and down, it passes the vertical line test, in green, but it doesn't pass the horizontal line test.

now, check the picture on the right-side, if we just restrict its domain to be squeezed to only between [0 , π], it passes the horizontal line test, and thus with that constraint in place, it's a one-to-one function and thus its inverse is also a function, with that constraint in place, or namely with that constraint, cos(x) and cos⁻¹(x) are both functions.

7 0
2 years ago
The table represents the total miles traveled, y, after a number of hours, x.
Annette [7]
60x=y

To find this answer, find what y/x=m would be for m
150/2.5=60
240/4= 60
330/5.5=60
420/7=60
3 0
3 years ago
Read 2 more answers
Need help please need help
klasskru [66]

Answer:

b.y=4

c. x=6

These are the answers hope this helps

7 0
2 years ago
A housepainter mixed 5 gal of blue paint with every 9 gal of yellow paint in order to make a
NikAS [45]

I think any of these would work

10;18

15;28

20;35

8 0
3 years ago
Read 2 more answers
Find all polar coordinates of point p where p = (6, -pi/5)
Lelu [443]
Given a point in coordinates form (r,\theta), one can compute the cartesian form like this:
(r\cos\theta,r\sin\theta )
We have:
r=6,\theta=-\dfrac{\pi}{5}
We get the cartesian form then:
\left(6\cos-\dfrac{\pi}{5},6\sin-\dfrac{\pi}{5}\right)
4 0
3 years ago
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