3 years ago

If I fail this I fail the quarter. please help appreciate it

Mathematics

1 answer:

Dafna1 [17]3 years ago

6 0

C causw it is used to be a difrent cuase it just is

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Olegator [25]

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From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin

borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

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$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

$C_{n,x} = \frac{12!}{4!(8)!} = 495$

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Step-by-step explanation:

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2 years ago

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Answer: C.

Step-by-step explanation:

C. is the only one with a 3 right next to the x. In 3x, 3 would be the coefficient)

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