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telo118 [61]
2 years ago
6

Determine the range of the function g of x is equal to negative square root of the quantity x squared plus 16 end quantity

Mathematics
1 answer:
vova2212 [387]2 years ago
5 0

Option A is correct. The range of the function  g(x)=-\sqrt{x^2+16} given above expressed as an interval notation is (–∞, ∞)

Given the function g(x)=-\sqrt{x^2+16}

  • We are to find the range of the function.

  • First, we can see that the value of x² inside the square root will always be a positive value no matter the domain values of x.

  • Since the input value exists on all real numbers, hence<em> the output values will also exist on all real numbers since the </em><em>range</em><em> is dependent on the values of the </em><em>domain.</em>

Hence the range of the function given above expressed as an interval notation is (–∞, ∞)

Learn more here: brainly.com/question/16724504

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3 0
2 years ago
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RUDIKE [14]

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Step-by-step explanation:

<u>1. What is the difference?</u>

  The sequence goes down by 5. This means that the formula will have -5n in it.

<u>2. Work out the term before the first term.</u>

    The first term is 3, and we know that the sequence goes up by 5. So, to get the term before 3 we would add 5.

3 + 5 = 8   Remember, this is positive 8. (+8)

<u>3. Put that term at the end of the equation. </u>

   We have -5n already and we just worked out the term before the first one which is positive 8 - so put that at the end of the equation.

-5n + 8  This is our answer!

Just to prove it works:

<em>Substitute:   n = term</em>

Lets see if we can get the 3rd term which is -7. (n = 3)

-5(3) + 8

-15 + 8 = -7

See, it works!

8 0
3 years ago
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8x + y = -16 ;
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