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telo118 [61]
2 years ago
6

Determine the range of the function g of x is equal to negative square root of the quantity x squared plus 16 end quantity

Mathematics
1 answer:
vova2212 [387]2 years ago
5 0

Option A is correct. The range of the function  g(x)=-\sqrt{x^2+16} given above expressed as an interval notation is (–∞, ∞)

Given the function g(x)=-\sqrt{x^2+16}

  • We are to find the range of the function.

  • First, we can see that the value of x² inside the square root will always be a positive value no matter the domain values of x.

  • Since the input value exists on all real numbers, hence<em> the output values will also exist on all real numbers since the </em><em>range</em><em> is dependent on the values of the </em><em>domain.</em>

Hence the range of the function given above expressed as an interval notation is (–∞, ∞)

Learn more here: brainly.com/question/16724504

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Answer:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

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Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

\hat p=0.64 estimated proportion of interest

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:  

Null hypothesis:p =0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

p_v =P(z>2.43)=0.0075 \approx 0.008  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

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10-x =5

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x= 5

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