Question

Determine the range of the function g of x is equal to negative square root of the quantity x squared plus 16 end quantity

Answer 1

Option A is correct. The range of the function  $g(x)=-\sqrt{x^2+16}$ given above expressed as an interval notation is (–∞, ∞)

Given the function $g(x)=-\sqrt{x^2+16}$

• We are to find the range of the function.

• First, we can see that the value of x² inside the square root will always be a positive value no matter the domain values of x.

• Since the input value exists on all real numbers, hence the output values will also exist on all real numbers since the range is dependent on the values of the domain.

Hence the range of the function given above expressed as an interval notation is (–∞, ∞)

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