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djverab [1.8K]
2 years ago
6

10-x=5 What is X???I need help

Mathematics
2 answers:
Bogdan [553]2 years ago
3 0

10-x =5

-x= 5-10

-x = -5

x= 5

<h2>Answer : x=5</h2>
Luba_88 [7]2 years ago
3 0

Answer:

what the other person said

Step-by-step explanation:

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The volume of sphere is increaseing
Artemon [7]

Volume of a sphere:

<em>V</em> = 4/3 <em>π</em> <em>r</em> ³

Differentiate <em>V</em> with respect to time <em>t</em> :

d<em>V</em>/d<em>t</em> = 4<em>π</em> <em>r</em> ² d<em>r</em>/d<em>t</em>

Surface area of a sphere:

<em>A</em> = 4<em>π</em> <em>r</em> ²

Differentiate <em>A</em> with respect to <em>t</em> :

d<em>A</em>/d<em>t</em> = 8<em>π</em> <em>r</em> d<em>r</em>/d<em>t</em>

<em />

You're given that the volume is increasing at a constant rate, d<em>V</em>/d<em>t</em> = 10 cm³/s, so

10 cm³/s = 4<em>π</em> <em>r</em> ² d<em>r</em>/d<em>t</em>

Solve for d<em>r</em>/d<em>t</em> (the rate of change of the sphere's radius):

d<em>r</em>/d<em>t</em> = 5/(2<em>π</em> <em>r</em> ²) cm³/s

Substitute this into the equation for d<em>A</em>/d<em>t</em> :

d<em>A</em>/d<em>t</em> = 8<em>π</em> <em>r</em> (5/(2<em>π</em> <em>r</em> ²) cm³/s)

d<em>A</em>/d<em>t</em> = 20/<em>r</em> cm³/s

At the moment the radius is <em>r</em> = 5 cm, the surface area is increasing at a rate of

d<em>A</em>/d<em>t</em> = 20/(5 cm) cm³/s = 4 cm²/s

When the surface area is increasing at a rate of d<em>A</em>/d<em>t</em> = 2 cm²/s, the radius <em>r</em> is such that

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which happens when the radius is

<em>r</em> = 20/2 (cm³/s) / (cm²/s) = 10 cm

4 0
3 years ago
How does making a frequency table or line plot help you see which value occurs most often in a data set?
klemol [59]

Answer:

A frequency table and a line plot show which value occurs most often. this is done by labeling every value. The person can clearly see the organized layedout numbers in a frequency table or line plot.

Step-by-step explanation:

If you have any questions feel free to ask in the comments.

4 0
2 years ago
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