What is the power set of s={1,2,3,4,5}

1 answer:

5 0

The power set P(X) of a finite set X is the set of all possible subsets of X. If X has n elements, then it has a total of 2ⁿ subsets.

For the set S = {1, 2, 3, 4, 5}, we have

• subsets with cardinality 0:

{ } (the empty set)

• subsets with cardinality 1:

{1}, {2}, {3}, {4}, {5}

• subsets with card. 2:

{1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4}, {3, 4}, {4, 5}

• subsets with card. 3:

{1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}

• subsets with card. 4:

{1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}

• subsets with card. 5:

{1, 2, 3, 4, 5}

Then P(S) is the set containing all of these sets,

{{}, {1}, {2}, {3}, …, {1, 2, 3, 4, 5}}

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Ok So I an taking algebra 1 and this question is really confusing me.

V125BC [204]

You use the arithmetic sequence formula and input the information given to you.
tn = a + (n-1)d
t(56) is what your looking for so don't worry about the tn.
a is your first term,
a = 15.
n is the position of the term you are looking for, n = 56.
And d is the common difference, you find this by taking t2 and subtracting t1. t2=18 and t1=15.
d = 18 - 15 = 3
Inputting it all into the formula you get,
t(56) = 15 + (56-1)(3)
term 56 = 180.
You use this formula to find any term in a sequence provided you are given enough info. You can also manipulate it if you are asked to find something else like the first term(a), common difference(d) or term position(n). It just depends on what the question is asking and what information you are given. :)
Hope this helps!