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natali 33 [55]
3 years ago
11

Order this starting from the smallest:

Mathematics
2 answers:
lara31 [8.8K]3 years ago
4 0
I think it might be easier to understand if i change decimals to fractions, so lets start ;)
15.249=15\frac{249}{1000}
15.3=15.300=15\frac{300}{1000}
15.05=15.050=15\frac{50}{1000}
15.009=15\frac{9}{1000}
15.25=15.250=15\frac{250}{1000}

denominators are the same so now you only have to compare numerators (biger numerator = greater fraction)

so:

15\frac{9}{1000}

it means that:


15.009
WITCHER [35]3 years ago
3 0
15.009
15.05
15.249
15.25
15.3

I believe is the correct order
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Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.
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Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

\displaystyle T_ n = ar^{n-1}

Where <em>T</em>ₙ<em> </em>is the <em>n</em>th term, <em>a</em> is the initial term, and <em>r</em> is the common ratio.

We are given that the fifth term <em>T</em>₅ = 96 and the eighth term <em>T</em>₈ = 768. In other words:

\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}

Substitute and simplify:

\displaystyle 96 = ar^4 \text{ and } 768 = ar^7

We can rewrite the second equation as:

\displaystyle 768 = (ar^4) \cdot r^3

Substitute:

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Hence:

\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2

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Using the first equation, we can solve for the initial term:

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In conclusion, of the given geometric sequence, the first term <em>a</em> is 6 and its common ratio <em>r</em> is 2.

7 0
2 years ago
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