Its called as Spawning...Hope this helps
The difference between the time of the heartbeat and the pulse makes the animal Pulse Deficit.
Answer:
If a DNA molecule has 30% Adenine the percentage of the other bases is Thymine: 30% Cytosine: 20% Guanine: 20%.
Explanation:
When the percentage that a base has in a DNA molecule is given, the percentage of the other bases can be known using the Chargaff's base pair rule.
A DNA molecule has the information of the genome of a living being, according to a specific sequence of its nitrogenous bases adenine, guanine, cytosine and thymine.
Chargaff was able to establish that in a DNA molecule the ratio of purine : pyrimidine of 1:1, so there must be the same amount of thymine as adenine and a similar amount of guanine for the cytosine, taking into account the complementarity of bases.
Taking into account the law of the base pair, if in a DNA chain there is 30% of Adenine, in the molecule there is:
- <em>Adenine 30%.
</em>
- <em>Thymine 30%.
</em>
- <em>Cytosine 20%.
</em>
- <em>Guanine 20%.
</em>
- <em>Total ..... 100%
</em>
In this case, the <u>Chargaff rule is useful to determine the percentage of nitrogenous bases that exist in a DNA molecule, knowing the percentage of a single base</u>.
Codominance<span> is a relationship between two versions of a gene. Individuals receive one version of a gene, called an allele, from each parent. If the alleles are different, the dominant allele usually will be expressed, while the effect of the other allele, called recessive, is masked.
Credit: The internet </span>
Answer:
The correct answer is 6 genotypes
Explanation:
The most known case is two alleles of one gene (A and a), and we know the possible genotypes formed are three: AA, Aa, aa. Therefore, for a given number of alleles n, we calculate the number of possible genotypes as the sum of integers between 1 and n.
- For 2 alleles (n=2, the sum of integers between 1 and 2): Genotypes= 1 + 2= 3
⇒ For 3 alleles (n=3, the sum of integers between 1 and 3): Genotypes= 1 + 2 + 3= 6
So, we have 6 genotypes for 3 alleles (W1, W2 and W3) and they are:
W1W1
W1W2
W1W3
W2W2
W2W3
W3W3
