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Vladimir79 [104]
2 years ago
11

The National Science Foundation (NSF) offers grants to students who are interested in pursuing a college education. The student

must be enrolled full time (12 credit hours or more), and hold a grade point average of 3.8. The NSF will pay $9,500 per year towards tuition for 4 years. The initial amount is placed into an account paying 7.8% compounded annually, and the tuition is drawn from the account until the remaining balance is zero dollars. Determine the initial amount invested by the NSF. Round your answer to the nearest dollar.
Mathematics
1 answer:
AlexFokin [52]2 years ago
8 0

Answer:31,606 explanation: took edg test

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Car Acosts $10 36 per 100 miles to drive, while car B costs $6.64 per 100 miles to drive How much more would car A cost to drive
Ulleksa [173]

Answer:

$21.58 or $21.576

Step-by-step explanation:

580 ÷ 100 = 5.8

$10.36 × 5.8 = $60.088

$6.64 × 5.8 = 33.512

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4 0
3 years ago
Read 2 more answers
Find the velocity and position vectors of a particle that has the given acceleration and the given initial velocity and position
stira [4]

Answer:

v(t) = (2t+1) \mathbb{i} +3t^2 \mathbb{j} +4t^3 \mathbb{k}

r(t) = (t^2+t) \mathbb{i} +(t^3+2) \mathbb{j} +(t^4 - 3) \mathbb{k}

Step-by-step explanation:

The velocity vector is the integral of the acceleration vector i.e.

v(t) = \int a(t) dt

v(t) = \int (2 \mathbb{i}+6t \mathbb{j} 12t^2 \mathbb{k}) dt

v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + C_1

When t=0, v(0) = \mathbb{i}. Inserting these values in v(t),

C_1= \mathbb{i}

v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + \mathbb{i}

v(t) = (2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}

The position vector is the integral of the velocity vector i.e.

r(t) = \int v(t) dt

r(t) = \int ((2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}) dt

r(t) = (t^2+t) \mathbb{i}+t^3 \mathbb{j} t^4 \mathbb{k} + C_2

When t=0, r(t) =2\mathbb{j}-3\mathbb{k}. Inserting these values in r(t),

C_2=2\mathbb{j}-3\mathbb{k}

r(t)= (t^2+t) \mathbb{i}+t^3 \mathbb{j}+ t^4 \mathbb{k} + 2\mathbb{j}-3\mathbb{k}

r(t) = (t^2+t) \mathbb{i}+(t^3+2) \mathbb{j}+ (t^4-3) \mathbb{k}

5 0
4 years ago
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Find the zeros (roots) of the following equations.
saw5 [17]
Hello,

f(1)=2-9+12-12+10-3=0 ===>(x-1)*....
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Zeros are 1/2,1,3,i,-i


6 0
4 years ago
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