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Masja [62]
2 years ago
8

Suppose that a classmate asked you why (2x + 112 is not (4x² + 1). What is your response to this classmate?

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
5 0

The given expression is the square of a binomial, such that:

(2x + 1)^2 = 4x^2 + 4x + 1

Then the correct option is C.

<h3>Are the expressions equivalent?</h3>

We want to see if:

(2x + 1)^2

Is equivalent to (4x^2 + 1).

First, this is false, let's prove that.

We have the square of a binomial (2x + 1)^2. Remember the general formula:

(a + b)^2 = a^2 + 2ab + b^2

So if we apply this to our expression we get:

(2x + 1)^2 = (2x)^2 + 2*2x*1 + 1^2 = 4x^2 + 4x + 1

Then, the correct option is C.

If you want to learn more about binomials, you can read:

brainly.com/question/15246027

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jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
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|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
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5 0
3 years ago
PLEASE HELP!!!!!!!!BRAINLIEST PLUS 50 POINTS
docker41 [41]

Use the quadratic formula to find:

x

=

1

±

√

85

5

Explanation:

5

x

2

−

10

x

−

12

is of the form  

a

x

2

+

b

x

+

c

with  

a

=

5

,  

b

=

−

10

and  

c

=

−

12

This has discriminant  

Δ

given by the formula:

Δ

=

b

2

−

4

a

c

=

(

−

10

)

2

−

(

4

×

5

×

−

12

)

=

100

+

240

=

340

=

2

2

⋅

85

This is positive, but not a perfect square, so the quadratic equation has a pair of irrational roots, given by the quadratic formula:

x

=

−

b

±

√

b

2

−

4

a

c

2

a

=

−

b

±

√

Δ

2

a

=

10

±

√

340

10

=

10

±

2

√

85

10

=

1

±

√

85

5

5 0
3 years ago
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