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torisob [31]
2 years ago
10

Write and solve a system of equations. Be sure to label the variables. The sum of two numbers is twelve. Two times the first num

ber minus three times the second number is four. What are the two numbers? Show and Explain all work.
Mathematics
1 answer:
adoni [48]2 years ago
7 0

The solution to the system of equations is x = 8, y = 4.

<h3>How to write the system of equations?</h3>

First, let's define our variables as x and y.

"the sum of two numbers is twelve" is written as:

x + y = 12

"two times the first number minus three times the second number is four" is written as:

2x - 3y = 4

Then the system of equations is:

x + y  = 12

2x - 3y = 4

<h3>How to solve it?</h3>

First, we isolate one of the variables in one equation, I will isolate x on the first one to get:

x = 12 - y

Now we replace this on the other equation, so we get:

2*(12 - y) - 3y = 4

Now we can solve this for y.

24 - 2y - 3y = 4

24 - 5y = 4

24 - 4 = 5y

20/5 = y = 4

Now we know the value of y, and:

x = 12 - y = 12 - 4 = 8

Then the solution of the system is:

x = 8, y = 4.

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

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Solve this system of equation using substitution y=2x-4 x+2y=10
Vladimir79 [104]
Y=2x-4
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Put y into the x equation
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Expand and simplify
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Insert x into the original equation to get y
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2 years ago
Six times a number is greater than 20 more than that number. What are the possible values of that number?
seropon [69]
It would be easier to translate this into mathematical terms first.
Let n = the unknown number

6n <span>> n + 20

Subtracting both sides by n to simplify:
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</span>5n <span>> 20
</span><span>
Dividing both sides by 5:
5n/5 </span><span>> 20/5
</span>n <span>> 4
</span><span>
Among the choices, the correct one is the second choice.

</span>
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3 years ago
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Step-by-step explanation:

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