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Law Incorporation [45]
3 years ago
9

What is the distance between (-2 1/2,3)and(1,-3)

Mathematics
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

3

Step-by-step explanation:

due to the fact I really don't know

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90 points please help!!!!!!!!
just olya [345]
To model this situation, we are going to use the exponential function: f(t)=P(1+ \frac{r}{n} )^{nt}
where
P is the initial number of cars
r is the growing rate in decimal form 
n is number of tames the growing rate is increasing per year
t is the time in years

To convert the growing rate to decimal form, we are going to divide the rate by 100%
r= \frac{12}{100}
r=0.12
Since the growing rate is increasing quarterly, n=4. We also know that the initial number of cars is 920, so P=920. Lets replace all those values in our function:
f(t)=920(1+ \frac{0.12}{4} )^{4t}
f(t)=920(1+0.03)^{4t}
f(t)=900(1.03)^{4t}

We can conclude that:
Rate ---------> The quarterly rate of growth is 0.03 or 3%
Exponent --------> The compound periods multiplied by the number of years                                 is 4t
Coefficient--------> The initial number of cars serviced is 920
Base------> The growth factor is represented by 1.03
3 0
3 years ago
Read 2 more answers
What is equivalent to (4xy-3z)^2 and<br> what type of special product is it?
sergey [27]

Answer:

the answer on edgenuty is option D

Step-by-step explanation:

i just took the quiz

3 0
3 years ago
Can i have help on this q plz
Alexandra [31]

Answer:

14.8

Step-by-step explanation:

7.4 * 2 = 14.8.

hope this helps

8 0
2 years ago
Read 2 more answers
Write 8:136 in the form of 1:n
sergeinik [125]

Answer:

1:17

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please answer the followings: W^mW^n=
Lunna [17]

Step-by-step explanation:

W^m=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m}\\\\W^n=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{n}\\\\W^mW^n=\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{m}\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{n}\\\\=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m+n}=W^{m+n}

5 0
3 years ago
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