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zlopas [31]
3 years ago
14

100 POINTS AND BRAINLIEST!! ONLY IF YOU GET IT CORRECT!!

Biology
2 answers:
adoni [48]3 years ago
7 0
  • They have to live in swallow water.Even if there are plenty of fishes they have to toil hard to get them as there mouth is too thin and long.
  • For which there mouth will be evolved to small size by which they can eat the fishes.
  • They will be adopted with ecoholocation by which they can find fishes easily
mihalych1998 [28]3 years ago
4 0

Answer:

Some adaptations that dolphin may develop to capture food are:

  • Since to capture fish its hard ,they may develop a big mouth to capture a fish quickly and easily.
  • By the help of echolocation they can find their food easily as there body may modified as needed.

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<span>one of the traits that make a good scientist accuracy of observation.</span>
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Fireflies emit flashes of light because of chemical reactions, which occur in their abdomens. The rate of the chemical reactions
damaskus [11]

Since the rate of flashing depends on the rate of reaction, it means that fireflies will flash slower during cold weather.

<h3>How does temperature affect rate of reactions?</h3>

Temperature affects the rate of reaction such that reactions are faster at high temperatures and slower at low temperatures.

Thus, since the rate of flashing in fireflies depends on the rate of reaction, cold temperature means that the rate of flashing will be low as compared to warm temperature.

In other words, fireflies will flash lower during cold weather and vice versa.

More on temperature and rate of reactions can be found here: brainly.com/question/16717828

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3 years ago
The following diagram shows where, in layers of rock, fossils of certain organisms are found.
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2 years ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
An experiment that____ a hypothesis will often provide a nee direction for the reseacher
SSSSS [86.1K]

Answer:

B

Explanation:

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