All categories

2 years ago

What value of x makes this equation true? -90=-100+X

Mathematics

1 answer:

WARRIOR [948]2 years ago

7 0

Answer:

-90=-100+x

-90+100=x

x=10

hence 10 is that value whose satisfy this equation

Step-by-step explanation:

You might be interested in

What is the value of x? 5 cm 3 cm Enter your answer in the box 40 cm 2x + 10

Monica [59]

Answer:

5cm

Step-by-step explanation:

3 0

3 years ago

Need help asap thanks

Ymorist [56]

Answer:

Step-by-step explanation:

for a right angled triangle, the sum of the square of the two sides should be equal to the square of the hypotenuse. If this rule does not hold, the dimensions do not represent the side of a right angled triangle.

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

4² + 10² ≠ 16²

6² + 12² = 13²

7² + 24² = 25²

8² + 15² = 17²

8 0

3 years ago

Answerrr?? What is the answer to these two questions?..

asambeis [7]

15. 16 yards. Add side a (2 yds.) and b (6 yds.), divide by 2 and then multiply by the height (4 yds.)

16. I believe it would be 48 m. find the area of each rectangle and then add it. (6x2)+(12x3) -> 12+36= 48 square meters.

Hope it helps! -cat

4 0

3 years ago

What is the value of x in the equation -2/3 x +9= 4/3x -3?

HACTEHA [7]

-2/3x+9=4/3x-3 original problem add 2/3x to both sides

9=6/3x-3 simplify 6/3 to 2 and add 3 to both sides

12=2x divide both sides by 2

x=6

hope that helps

5 0

4 years ago

find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s mor

Oksanka [162]

Answer:

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is: $y = -x^2+8x-12$

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

$y = -x^2+8x-12\\0 = -x^2+8x-12\\x^2-8x+12=0$

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

$x^2-8x+12=0\\x^2-2x-6x+12=0\\(x^2-2x)+(-6x+12)=0\\x(x-2)-6(x-2)=0\\(x-2)(x-6)=0$

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

3 0

3 years ago