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3 years ago

Find the simple interest paid on a loan of $4,750 at a rate of 19.5% for 30 months.

Mathematics

1 answer:

Kazeer [188]3 years ago

8 0

Answer:

Monthly Payment $201.31

Total Interest Paid $1,289.26

Total Paid $6,039.26

Step-by-step explanation:

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Find the value of $x$ for the right triangle. A right triangle with base labeled x and hypotenuse labeled 12 units. Angle betwee

slamgirl [31]

Answer:

6 feets

Step-by-step explanation:

The triangle described in the question has been sketched in the picture attached below :

From the triangle, we could solve for X, which is the base of the triangle using trigonometry :

Sinθ = opposite / hypotenus

Sin 30° = x / 12

0.5 = x / 12

x = 12 * 0.5

x = 6 feets

Hence base, x = 6 feets

8 0

3 years ago

A sum amount <br>to rupees 34476 in two and a half years at 4% CI. the sum is

Kruka [31]

Given:

Amount = Rs. 34476

Rate of compound interest = 4%

Time = $2\dfrac{1}{2}=2.5$ years

To find:

The principal value.

Solution:

Formula for amount is

$A=P\left(1+\dfrac{r}{100}\right)^t$

Where, P is principal value, r is rate of interest and t is time in years.

Putting the given values, we get

$34476=P\left(1+\dfrac{4}{100}\right)^{2.5}$

$34476=P\left(1+0.04\right)^{2.5}$

$34476=P\left(1.04\right)^{2.5}$

$\dfrac{34476}{\left(1.04\right)^{2.5}}=P$

Now,

$P=31256.0090$

$P\approx 31256$

Therefore, the value of sum or principal value is Rs.31256.

6 0

3 years ago

The diameter of the circle is 8 cm. what is the circles area?

iren [92.7K]

Answer:

Step-by-step explanation:

diameter = 8 cm

radius = 8/2 = 4 cm

Area of circle = πr²

= 3.14*4*4 = 50.24 cm²

8 0

4 years ago

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Which is a graph of x^2/25 + y^2/4= 1

AVprozaik [17]

Answer:

If your answer is multiple choice, try to look for a graph that matches these intercepts. I hope this helped you. Have a great rest of your day!

7 0

3 years ago

Solve the system using substitution x+5y=0 3y+2x=-21

Crazy boy [7]

Answer:

$\left \{ {{x = -15} \atop {y=3}} \right.$

Step-by-step explanation:

$\left \{ {{x + 5y = 0} (1) \atop {3y + 2x = -21}(2)} \right. \left \{ {{x = -5y} \atop {3y + 2x = -21}} \right. \left \{ {{x = -5y} \atop {3y + 2*(-5y) = -21}} \right. \left \{ {{x = -5y} \atop {3y - 10y = -21}} \right. \\ \left \{ {{x = -5y } \atop {-7y = -21}} \right. \left \{ {{x = -5y} \atop {y= 3 }} \right. \left \{ {{x = -5 * 3} \atop {y=3}} \right.=> \left \{ {{x=-15} \atop {y=3}} \right.$

5 0

3 years ago

Read 2 more answers