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deff fn [24]
2 years ago
5

A gardening box is 412 yd by 212 yd by 34 yd. What is the maximum amount of planting soil that can be used to fill the gardening

box? 8716 yd³ 8316 yd³ 734 yd³ I don't know.
Mathematics
2 answers:
Nat2105 [25]2 years ago
8 0

The amount of soil in the gardening box is an illstration of volume

The maximum amount of planting soil that can be used to fill the gardening box is 2969696 cubic yards

<h3>How to determine the amount of planting soil needed</h3>

The dimension of the gardening box is given as:

Length = 412 yd

Width = 212 yd

Height = 34 yd

Assume that the dimensions of the gardening box are not too thick.

The volume of the box is the product of its dimensions.

So, we have:

Volume = 412 yd * 212 yd * 34 yd

This gives

Volume = 2969696 cubic yards

Hence, the amount of soil that can be used to fill the gardening box is 2969696 cubic yards (none of the options is correct)

Read more about volumes at:

brainly.com/question/1972490

sveta [45]2 years ago
5 0

Answer:

THE ANSWER IS DOWN BELOW :)

Step-by-step explanation:

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Which of the following is the sum of all the odd integers between 5 and 102?
STALIN [3.7K]

Answer:

2601

Step-by-step explanation:

The integers between 5 and 102 are

7, 9, 11, 13, 15, 17,19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99, 101

The sum of the odd intergers between 2 and 105 can be calculated as follows

= (N + 1/2)^2

= (101 + 1 /2) ^2

= (102/2)^2

= 51^2

= 2601

Hence the sum of the odd intergers between 5 and 102 is 2601

3 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
F(n+1)=f(n)-5. If f(1)=100, what is f(6)
PilotLPTM [1.2K]

Answer:

<em>75</em>

Step-by-step explanation:

Given:

f(1) = 100

f(n+1) = f(n) - 5

Solve for:

f(6)

Solution:

f(1) = 100

f(2) = f(1) - 5 = 100 - 5 = 100 - 1 x 5 = f(1) - 1 x 5

f(3) = f(2) - 5 = 100 - 5 - 5 = 100 - 2 x 5 = f(1)  - 2 x 5

...

f(n) = f(n - 1) - 5 = 100 - (n-1) x 5 = f(1) - (n-1) x 5

=> f(6) = f(1) - (6-1) x 5 = 100 - 5 x 5 = 100 - 25 = 75

Hope this helps!

8 0
3 years ago
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
8 months ago
Quadrilateral ABCD is a square. BC = 10 What is the length of AC? A. 10 sqrt 2 B. 20 sqrt 3 C. 10 sqrt 3 D. Sqrt 100
bixtya [17]

A is the correct answer to this question because AC and BC differ because the B must be changed to an A.

4 0
3 years ago
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