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Irina-Kira [14]
3 years ago
15

what is an equation of the line that passes through the point (5,1) and is parallel to the line x+y=9

Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0
Y=9-x is slope-intercept form of that line, which means it has a slope of -1. Parallel lines have the same slope, so the slope of this new line will also be -1.

To find the line that goes through (5,1), we can use a blank equation y=mx+b. We know that m=-1, so we can use the given point to find b:

y=mx+b
Y=-x+b
1=-5+b
6=b

So the line would be y=-x+6.
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4 0
3 years ago
In triangle XYZ, let angle Y be a right angle, mZ = 54°, and YZ = 361. Find the area of the
laiz [17]

Answer:

89,709

Step-by-step explanation:

∡Z= 54°

tan 54 = XY / 361

XY = 361 · tan 54°

XY = 497

A = 1/2 (361) (497)

5 0
2 years ago
Multiply 3(2x - 1)(x + 2)
Andrei [34K]
(6x-3)(3x+6)


Explanation:
3 0
3 years ago
Can someone please please help me
Alekssandra [29.7K]

Answer:

The answer is None

Step-by-step explanation:

Multiply 6 2 and 1 and also multiply 12 4 and 2 separately now divide 96 with 12 and you get 8 which is none of the answer choices

6 0
3 years ago
Read 2 more answers
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
3 years ago
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