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1 year ago

7

The function y=-16t^2 +36 represents the height y (in feet) of a water droplet t seconds after falling from an icicle. After how

many seconds
does the water droplet hit the ground?

1 answer:

NikAS [45]1 year ago

3 0

Answer:

1.5 seconds

Step-by-step explanation:

plug 0 in for y

0=-16t^2+36

then slove for t

-36=-16t^2

-36 / -16 = 9/4

9/4=t^2

square root of 9/4 is 3/2 or 1.5

t=1.5

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Step-by-step explanation:

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Write a quadratic function to model the vertical motion for each situation, given h(t) equals negative 16t squared plus v0t+h0

Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

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t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

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Answer:

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