Answer:
0.13% of customers spend more than 46 minutes
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What percentage of customers spend more than 46 minutes?
This is 1 subtracted by the pvalue of Z when X = 46. So



has a pvalue of 0.9987
1 - 0.9987 = 0.0013
0.13% of customers spend more than 46 minutes
Answer:
your just finding area so
1.5×2.5=
1.5×1.5/2=
1.5×2.5=
I will put the answers in the comments I need to use a calculator
The first answer is 1310
2.300 seats total
3.and im sorry i cant help u with this one
Lets change "16" by its to 16/1 .. since nothing can't help support 16 by itself when it is going into 7/10
Now that we change that ... your problem becomes 7/10 × 16/1
7/10 × 16/1 = 11 1/5
Because
7(16) / 10(1) = 112/10
Now lets go. to how we solve the for the answer
112/10 = 11 1/5
☺