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Furkat [3]
4 years ago
12

You have just arrived at summer camp. And your cabin, the counselor has each camper perform the super secret handshake with ever

y other person in the cabin. You and another person or in the cabin, so there is one handshake. Another person arrives, and another, until there are 14 people in the cabin. How many handshakes will there be an all?
Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
8 0
Just try to follow my description. When two persons are in the cabin, there is only 1 handshake. When a third person comes, he will have to handshake the two people who came before him. So, there will be 2 handshakes. When a fourth person comes, he would make 3 handshakes with the 3 people who came before him. When the fifth person comes, he would make 4 handshakes with the 4 people who came before him. So, you see there is a pattern. The number of handshakes is 1 less than the total number of people inside the cabin. So, if there are 14 people in the cabin, the last person to come in would have to make 13 handshakes with the 13 people who came in first. Obtaining the sum of all the handshakes starting from the 2 handshakes initially to the 13 handshakes, the sum would be

Total handshakes = 2+3+4+5+6+7+8+9+10+11+12+13
Total handshakes = 90

Therefore, there will be a total of 90 handshakes made within the cabin of 14 people.
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8 0
3 years ago
An orange juice company sells a can of frozen orange juice that measures 9.4 centimeters in height and 5.2 centimeters in diamet
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<h2>Hello!</h2>

The answer is:

The third option:

2.7 times as much.

<h2>Why?</h2>

To calculate how many more juice will the new can hold, we need to calculate the old can volume to the new can volume.

So, calculating we have:

Old can:

Since the cans have a right cylinder shape, we can calculate their volume using the following formula:

Volume_{RightCylinder}=Volume_{Can}=\pi r^{2} h

Where,

r=radius=\frac{diameter}{2}\\h=height

We are given the old can dimensions:

radius=\frac{5.2cm}{2}=2.6cm\\\\height=9.4cm

So, calculating the volume, we have:

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We have that the volume of the old can is:

Volume_{Can}=199.7cm^{2}

New can:

We are given the new can dimensions, the diameter is increased but the height is the same, so:

radius=\frac{8.5cm}{2}=4.25cm\\\\height=9.4cm

Calculating we have:

Volume_{Can}=\pi *4.25cm^{2} *9.4cm=533.40cm^{3}

Now, dividing the volume of the new can by the old can volume to know how many times more juice will the new can hold, we have:

\frac{533.4cm^{3} }{199.7cm^{3}}=2.67=2.7

Hence, we have that the new can hold 2.7 more juice than the old can, so, the answer is the third option:

2.7 times as much.

Have a nice day!

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Use secant-tangent product theorem.

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