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KIM [24]
2 years ago
12

URGENT O_O Find the roots of the polynomial equation! 2x^3+2x^2-19x+20=0

Mathematics
1 answer:
ohaa [14]2 years ago
4 0

The function is

  • y=2x^3+2x^2-19x+20

Graph attached

There is one real zero only

That's-1.047

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Is this correct help plzz
const2013 [10]
None of the offered choices is correct.

The radical cannot be simplified. If rewritten, it must be written as something like
x \sqrt[3]{ \frac{6}{x}}
or
\frac{6x}{ \sqrt[3]{36x}}
3 0
3 years ago
Write each equation in standard form. identify A,B,C.
aleksley [76]
Write in y=ax²+bx+c form
solve for y

given
\frac{x+5}{3}=-2y+4
solve for y

easy
minus 4 both sides
\frac{x+5}{3}-4=-2y
times -1/2 to both sides
\frac{x+5}{-6}+2=y
y=\frac{x+5}{-6}+2
y=\frac{-x}{6}-\frac{6}{5}+2
2=10/5
y=\frac{-1}{6}x-\frac{6}{5}+\frac{10}{5}
y=\frac{-1}{6}x+\frac{4}{5}
y=ax²+bx+c
y=0x^2+\frac{-1}{6}x+\frac{4}{5}

a=0
b=\frac{-1}{6}
c=\frac{4}{5}
3 0
2 years ago
What is the range of possible sizes for side x?<br> 3.2<br> x<br> 5.5
ladessa [460]

Answer: try multiplication for the answer or use photomath

Step-by-step explanation:

3 0
2 years ago
For the function below, state the x-coordinate of the x-intercept that is located to the fight of the origin.
OLga [1]

Answer:

x = 3

Step-by-step explanation:

It should NOT be "fight of the origin", rather "right of the origin".

Now let's move on to solve the question...

The x-intercept is found by setting the function equal to 0. Thus:

0 = x^3 - 9x

<em>Let's solve this using algebra:</em>

<em>0=x^3-9x\\0=x(x^2-9)\\0=x(x-3)(x+3)</em>

<em />

<em>Hence, x = -3 and x = 3</em>

<em />

The coordinate that is to the right of the origin is the positive one, so x = 3 is the x-intercept we are looking for.

3 0
3 years ago
Read 2 more answers
Jessica owns 1/8 of a company worth $56,000. What is the value of
rosijanka [135]
7000

1/8th in percentage form is 12.5%
12.5% of 56000 is 7000
8 0
2 years ago
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